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    I'm just looking over some maths challenge questions and since I'm awful at geometry based stuff I can't see a way to do this. I know what the answer should be, but if someone could show a decent method that'd be great.

    T is 4
    Name:  87fb2822a82944f28765b2cccd510628.png
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    The answer is 9
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    (Original post by Bruhh)
    I'm just looking over some maths challenge questions and since I'm awful at geometry based stuff I can't see a way to do this. I know what the answer should be, but if someone could show a decent method that'd be great.

    T is 4
    Name:  87fb2822a82944f28765b2cccd510628.png
Views: 26
Size:  39.6 KB

    Answer:
    Spoiler:
    Show


    The answer is 9

    We need the value of T.

    What have you got so far?
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    (Original post by Muttley79)
    We need the value of T.

    What have you got so far?
    I put that in the OP, T is 4.
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    (Original post by Bruhh)
    I put that in the OP, T is 4.
    Sorry, I missed it -

    What have you tried?

    We know the area of the trapezium and something about the two parallel sides so ...
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    (Original post by Muttley79)
    Sorry, I missed it -

    What have you tried?

    We know the area of the trapezium and something about the two parallel sides so ...
    Well I have (3*AE*h)/2 = 27 where h is the height of the trapezium

    I'm not sure how to use the fact F is the midpoint, other than that CF=BF obviously.
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    (Original post by Bruhh)
    Well I have (3*AE*h)/2 = 27 where h is the height of the trapezium

    I'm not sure how to use the fact F is the midpoint, other than that CF=BF obviously.
    OK so we can say Ah = 18?

    Then find the area of each of the triangles ...[think about the heights of the two on the right]

    Then subtract from the area of the trapezium.
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    (Original post by Muttley79)
    OK so we can say Ah = 18?

    Then find the area of each of the triangles ...[think about the heights of the two on the right]

    Then subtract from the area of the trapezium.
    Ah yes I've got it! Thanks for that.
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    (Original post by Bruhh)
    Ah yes I've got it! Thanks for that.
    You could also look at the fraction of the trapezium shaded.
 
 
 
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