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# How would you solve this question only using C1 knowledge? Part c btw. watch

It might be easier to see if you factorise, take (x-1) out as a common factor.
2. I already solved it by using Algebraic long division, the answers are 3,1,-1. The issue is that for a C1 question without a calculator it might be a bit hard, also it's worth only 3 marks.
3. it is related to the original function by a simple translation. thus the roots will be translated by the same amount.
I already solved it by using Algebraic long division, the answers are 3,1,-1. The issue is that for a C1 question without a calculator it might be a bit hard, also it's worth only 3 marks.
Seems alright for a 3 marker.

If you take out (x-1) you get:
= (x - 1)[(x - 1)^2 - 4]

= (x - 1)[x^2 -2x +1 - 4]

= (x - 1)[x^2 -2x - 3]

= (x - 1)(x - 3)(x + 1)

Giving you x = 1, 3, -1

You don't actually have to go through long division which is general a slower process, I think just taking time to take out a common factor and expand the quadratic would only take a minute with some practice.

Good luck!
5. Ok done took the (x-1), that does make it easier thanks @notnotbatman
Ok done took the (x-1), that does make it easier thanks @notnotbatman
if you observe carefully and let the original function =f(x) then the curve they want you to draw is f(x-1) which you should be able to draw from the original graph, the solutions can also be found easily using this way after drawing the graph
7. You shouldn't have to do the actual expansions.
You've been given y = x^3 - 4x which we can call f(x).
y = (x-1)^3 - 4(x-1) can be written as f(x-1) since the 'x' values are replaced by 'x-1'.

From simple graph transformations, you know that f(x - a) translates the graph 'a' units horizontally, so in your question, the original graph is just translated 1 unit to the right. This means you can easily state the roots and the turning point, allowing you to sketch the curve
8. Good grief folks. Listen to the beaɾ .
9. (Original post by Mr M)
Good grief folks. Listen to the beaɾ .

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Updated: January 18, 2017
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