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How would you solve this question only using C1 knowledge? Part c btw. Watch

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    (Original post by ImBadAtLife)
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    It might be easier to see if you factorise, take (x-1) out as a common factor.
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    I already solved it by using Algebraic long division, the answers are 3,1,-1. The issue is that for a C1 question without a calculator it might be a bit hard, also it's worth only 3 marks.
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    it is related to the original function by a simple translation. thus the roots will be translated by the same amount.
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    (Original post by ImBadAtLife)
    I already solved it by using Algebraic long division, the answers are 3,1,-1. The issue is that for a C1 question without a calculator it might be a bit hard, also it's worth only 3 marks.
    Seems alright for a 3 marker.

    If you take out (x-1) you get:
    = (x - 1)[(x - 1)^2 - 4]

    = (x - 1)[x^2 -2x +1 - 4]

    = (x - 1)[x^2 -2x - 3]

    = (x - 1)(x - 3)(x + 1)

    Giving you x = 1, 3, -1

    You don't actually have to go through long division which is general a slower process, I think just taking time to take out a common factor and expand the quadratic would only take a minute with some practice.

    Good luck!
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    Ok done took the (x-1), that does make it easier thanks @notnotbatman
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    (Original post by ImBadAtLife)
    Ok done took the (x-1), that does make it easier thanks @notnotbatman
    if you observe carefully and let the original function =f(x) then the curve they want you to draw is f(x-1) which you should be able to draw from the original graph, the solutions can also be found easily using this way after drawing the graph
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    You shouldn't have to do the actual expansions.
    You've been given y = x^3 - 4x which we can call f(x).
    y = (x-1)^3 - 4(x-1) can be written as f(x-1) since the 'x' values are replaced by 'x-1'.

    From simple graph transformations, you know that f(x - a) translates the graph 'a' units horizontally, so in your question, the original graph is just translated 1 unit to the right. This means you can easily state the roots and the turning point, allowing you to sketch the curve
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    Good grief folks. Listen to the beaɾ .
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    (Original post by Mr M)
    Good grief folks. Listen to the beaɾ .
    :hat2:
 
 
 
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