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    How do I solve this question please?

    A curve has the equation y=e^2x(x^2-4x-2)
    A) find the value of the x coordinate of each of the stationary points of the curve
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    (Original post by Lucy373)
    How do I solve this question please?

    A curve has the equation y=e^2x(x^2-4x-2)
    A) find the value of the x coordinate of each of the stationary points of the curve
    What is he first word that comes to mind when you see 'stationary points'?
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    (Original post by SeanFM)
    What is he first word that comes to mind when you see 'stationary points'?
    dy/dx=0
    But not sure how to differentiate it?
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    (Original post by Lucy373)
    dy/dx=0
    But not sure how to differentiate it?
    Since you have one function of x multiplied by another, you would use the .........? rule

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    (Original post by Lucy373)
    dy/dx=0
    But not sure how to differentiate it?
    If you said f(x) = e^2x and g(x) = the quadratic... does that help?
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    (Original post by SeanFM)
    If you said f(x) = e^2x and g(x) = the quadratic... does that help?
    Sorry not really I know to use the product rule and I got dy/dx=e^2x(2x^2-6x-8) do you know if this is right?
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    (Original post by Lucy373)
    Sorry not really I know to use the product rule and I got dy/dx=e^2x(2x^2-6x-8) do you know if this is right?
    That is 50% of the answer. You have correctly found u'v but not uv' in the product rule of the form (uv)' = u'v + v'u if that is the notation you are used to.
 
 
 
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