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1. How do I solve this question please?

A curve has the equation y=e^2x(x^2-4x-2)
A) find the value of the x coordinate of each of the stationary points of the curve
2. (Original post by Lucy373)
How do I solve this question please?

A curve has the equation y=e^2x(x^2-4x-2)
A) find the value of the x coordinate of each of the stationary points of the curve
What is he first word that comes to mind when you see 'stationary points'?
3. (Original post by SeanFM)
What is he first word that comes to mind when you see 'stationary points'?
dy/dx=0
But not sure how to differentiate it?
4. (Original post by Lucy373)
dy/dx=0
But not sure how to differentiate it?
Since you have one function of x multiplied by another, you would use the .........? rule

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5. (Original post by Lucy373)
dy/dx=0
But not sure how to differentiate it?
If you said f(x) = e^2x and g(x) = the quadratic... does that help?
6. (Original post by SeanFM)
If you said f(x) = e^2x and g(x) = the quadratic... does that help?
Sorry not really I know to use the product rule and I got dy/dx=e^2x(2x^2-6x-8) do you know if this is right?
7. (Original post by Lucy373)
Sorry not really I know to use the product rule and I got dy/dx=e^2x(2x^2-6x-8) do you know if this is right?
That is 50% of the answer. You have correctly found u'v but not uv' in the product rule of the form (uv)' = u'v + v'u if that is the notation you are used to.

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