A smooth slope is inclined at tan−143 to the horizontal. A body of mass 4kg is released from rest at the top of the slope and reachers the bottom with speed 7 m/s. Find the length of the slope.
This is meant to be done using energy and work done.
I am not entirely sure about all the forces here. Will the tractive force T include the 4gsinα or be as well as it? Am I on the right track?
1. Find the resultant of the forces along the plane. Smooth, no friction, so the resultant is simply a component of weight. 2. Use F=ma to find acceleration. 3. Use uvast to calculate the distance.
Or if you use energy and work done (didn't read your post fully) then it would be KE=GPE to get a vertical height. That and the angle is enough to work out the hypotenuse.
A smooth slope is inclined at tan−143 to the horizontal. A body of mass 4kg is released from rest at the top of the slope and reachers the bottom with speed 7 m/s. Find the length of the slope.
This is meant to be done using energy and work done.
I am not entirely sure about all the forces here. Will the tractive force T include the 4gsinα or be as well as it? Am I on the right track?
Many thanks in advance
Since it's a smooth slope you have GPE Lost = KE Gained.
And they're the only two things you need to worry about. You don't need to work out the component of weight down the slope - energy takes care of all that for you.