The mark scheme saids " E of redox system 5 is more negative but not than that of redox systems 2&1
Redox system 5 is +0.17 (positive ?)
Redox systems Watch
- Thread Starter
- 22-01-2017 14:06
- Community Assistant
- Study Helper
- 22-01-2017 20:09
If sulfur(IV) oxide is being bubbled through then it is the species being oxidised.
Calculate the hypothetical cell values from Ecell = E(red) - E(ox)
A positive value means a feasible reaction, a negative value means no reaction.