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    • Thread Starter

    (Original post by RDKGames)
    Cant check if thats correct right now, but you essentially need to equate the real and imaginary parts of both sides of the equation.

    Posted from TSR Mobile
    Well thats what I tried doing but its giving me a weird answer of y=-3x-3 wtf? :/
    • Community Assistant

    Community Assistant
    (Original post by English-help)
    Well thats what I tried doing but its giving me a weird answer of y=-3x-3 wtf? :/
    While skimming through your last post, I think your second line isn't true. (Unless i misread the LHS ...

    Anyways, working from the first, equating the reals gives you:


    Equating the imaginaries gives:


    Now solve these as simultaneous equations

    Posted from TSR Mobile

    You can certainly do this the simultaneous equations way. An alternative method (for a different fraction so as not to give a full solution).

    Suppose we wanted to solve z/(2+z) = 4-2i. (Again, this is not the same as the problem you asked. You can follow this method and apply to your problem though).

    Multiply across to get z = (4-2i)(2+z). Then z - (4-2i)z = (4-2i)2 = 8-4i.

    So (1-(4-2i))z = 8 - 4i, so -(3-2i)z = 8 - 4i.

    Now multiply both sides by the complex conjugate of 3-2i (i.e. 3+2i) to get

    -(3-2i)(3+2i)z = (8 - 4i)(3+2i)

    That is, -13z = 24 + 8 -12i+16i = 32+4i

    So z = -(32+4i)/13 = -\dfrac{32}{13} - i\dfrac{4}{13}
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Updated: January 25, 2017
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