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    (Original post by RDKGames)
    Cant check if thats correct right now, but you essentially need to equate the real and imaginary parts of both sides of the equation.


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    Well thats what I tried doing but its giving me a weird answer of y=-3x-3 wtf? :/
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    (Original post by English-help)
    Well thats what I tried doing but its giving me a weird answer of y=-3x-3 wtf? :/
    While skimming through your last post, I think your second line isn't true. (Unless i misread the LHS ...

    Anyways, working from the first, equating the reals gives you:

    x=2x-3y+2

    Equating the imaginaries gives:

    y=3x+2y+3

    Now solve these as simultaneous equations


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    You can certainly do this the simultaneous equations way. An alternative method (for a different fraction so as not to give a full solution).

    Suppose we wanted to solve z/(2+z) = 4-2i. (Again, this is not the same as the problem you asked. You can follow this method and apply to your problem though).

    Multiply across to get z = (4-2i)(2+z). Then z - (4-2i)z = (4-2i)2 = 8-4i.

    So (1-(4-2i))z = 8 - 4i, so -(3-2i)z = 8 - 4i.

    Now multiply both sides by the complex conjugate of 3-2i (i.e. 3+2i) to get

    -(3-2i)(3+2i)z = (8 - 4i)(3+2i)

    That is, -13z = 24 + 8 -12i+16i = 32+4i

    So z = -(32+4i)/13 = -\dfrac{32}{13} - i\dfrac{4}{13}
 
 
 
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