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Further Pure 1 help watch
- Thread Starter
- 25-01-2017 14:10
- Community Assistant
(Original post by English-help)
- 25-01-2017 15:17
Well thats what I tried doing but its giving me a weird answer of y=-3x-3 wtf? :/
Anyways, working from the first, equating the reals gives you:
Equating the imaginaries gives:
Now solve these as simultaneous equations
Posted from TSR MobileLast edited by RDKGames; 25-01-2017 at 15:21.
- 25-01-2017 16:55
You can certainly do this the simultaneous equations way. An alternative method (for a different fraction so as not to give a full solution).
Suppose we wanted to solve z/(2+z) = 4-2i. (Again, this is not the same as the problem you asked. You can follow this method and apply to your problem though).
Multiply across to get z = (4-2i)(2+z). Then z - (4-2i)z = (4-2i)2 = 8-4i.
So (1-(4-2i))z = 8 - 4i, so -(3-2i)z = 8 - 4i.
Now multiply both sides by the complex conjugate of 3-2i (i.e. 3+2i) to get
-(3-2i)(3+2i)z = (8 - 4i)(3+2i)
That is, -13z = 24 + 8 -12i+16i = 32+4i
So z = -(32+4i)/13 =