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    I'm seriously stuck on this FP1 question and the mark scheme is making very little sense.
    Name:  16325465_1018725781566563_1889311332_o.jpg
Views: 26
Size:  13.8 KB

    This is what I've done so far:

    Attachment 614144614146

    Any help appreciated x
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    (Original post by NiamhM1801)
    I'm seriously stuck on this FP1 question and the mark scheme is making very little sense.
    Name:  16325465_1018725781566563_1889311332_o.jpg
Views: 26
Size:  13.8 KB

    This is what I've done so far:

    Any help appreciated x
    So just slide a cheeky 2^k into the bracket being multiplied by 6 giving you: f(k+1)=2\cdot 2^{k}+6(6^k+2^k)-6\cdot 2^k
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    (Original post by NiamhM1801)
    I'm seriously stuck on this FP1 question and the mark scheme is making very little sense.
    Name:  16325465_1018725781566563_1889311332_o.jpg
Views: 26
Size:  13.8 KB

    This is what I've done so far:

    Attachment 614144614146

    Any help appreciated x
    From your last step, go to 2(2^k)=6(2^k)-4(2^k)
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    (Original post by RDKGames)
    So just slide a cheeky 2^k into the bracket being multiplied by 6 giving you: f(k+1)=2\cdot 2^{k}+6(6^k+2^k)-6\cdot 2^k
    What would be the point in doing that though? If you're only going to subtract it afterwards?

    (Original post by h3rmit)
    From your last step, go to 2(2^k)=6(2^k)-4(2^k)
    How though?

    feel like i'm missing something super obvious aaaa
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    (Original post by NiamhM1801)
    What would be the point in doing that though? If you're only going to subtract it afterwards?



    How though?

    feel like i'm missing something super obvious aaaa
    Because then you obtain f(k) in the expression.
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    (Original post by NiamhM1801)
    What would be the point in doing that though? If you're only going to subtract it afterwards?



    How though?

    feel like i'm missing something super obvious aaaa
    It's an equivalent statement, so just make the statement because you can so you can show what the question asks. Like C1 Indices
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    (Original post by RDKGames)
    Because then you obtain f(k) in the expression.
    Name:  16325981_1018774291561712_997952857_o.jpg
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    (Original post by NiamhM1801)
    Have I done it?
    Yep.
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    (Original post by RDKGames)
    Yep.
    Ah brilliant - thank you!!
 
 
 
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