Hereis the question:
I get how the resistance decreases in the LDR, and I would have gotten all the marks. I have a question though.
The mark scheme says When the LDR resistance is reduced, that decreases the pd across the LDR, OR increases the pd across the fixed resistor.
I get how a lower LDR resistance means a lower pd across the LDR, as V=IR so a smaller value of R would mean a smaller value of V.
However, I don't get how a lower LDR resistance would mean the pd would increase across the fixed resistor. I know the current would be the same everywhere in the circuit (series circuit)., Why would the pd increase across the fixed resistor? i don't get that, as R doesn't change, so V=IR, why would that increase the value of V?
Thanks