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    Dear friends,

    I cannot find the range of this reciprocal function: 1/(x+1) whose domain is
    {x:x≥0, x a real number}.

    I could draw the graph of this function but my confusion is if x-values are getting bigger from 0, then y-values are getting closer to 0 or approaching infinity, which means y-values are not getting bigger as x-values get bigger. Then how do I write the range?

    Thanks in advance.
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    (Original post by tantrik)
    Dear friends,

    I cannot find the range of this reciprocal function: 1/(x+1) whose domain is
    {x:x≥0, x a real number}.

    I could draw the graph of this function but my confusion is if x-values are getting bigger from 0, then y-values are getting closer to 0 or approaching infinity, which means y-values are not getting bigger as x-values get bigger. Then how do I write the range?

    Thanks in advance.
    Well yes, with your function y=\frac{1}{x+1} you have y\rightarrow 0 as x\rightarrow \infty so your range will be 0<y\leq a where a is the maximum value that the function takes.
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    (Original post by RDKGames)
    Well yes, with your function y=\frac{1}{x+1} you have y\rightarrow 0 as x\rightarrow \infty so your range will be 0<y\leq a where a is the maximum value that the function takes.
    Thanks for the solution. Highly appreciate it.
 
 
 
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