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    Water waves are viewed with a stroboscope. The wavelength is 10cm and the amplitude is 2cm. Calculate the wave displacement at 8cm and 35cm.
    (No other info was given!)
    Any help much appreciated! Thanks

    I'm not a hundred pecent sure (I'm still doing GCSEs), but all waves are in the form of a sine wave. So this particular wave could be modelled mathematically in the form y = 2sin(x * 2pi / 10). I got the expression from transforming y = sin(x) to be twice as tall (since the amplitude is 2, while sine is normally 1 at its highest point) and also stretch it out by a factor of 10/2pi, since the wavelength of sine is normally 2pi, but we need it to be 10. X here is the distance in cm along the line of the transfer of energy of the wave and y is the displacement in cm at that point. So at 8 cm, the displacement would be -1.90cm (3sf) and at 35cm, the displacement would be 0cm.

    Someone might need to correct me.
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