Original post by APersonYo
IO3-+ 5I- + 6H+ -> 3I2 + 3H2O
2 S2 O3 2- + 3I2 -> 6I- + S4 O6 2-
1 mol of IO3- produces 3 mol of I2
3 mol of I2 reacts with 2 mol of S2 o3 2-
So 1 mol of IO3- is equivalent to S2 O3 2-
HOW DOES THAT MAKE SENSE?
2 S2 O3 2- + 3I2 -> 6I- + S4 O6 2-
1 mol of IO3- produces 3 mol of I2
3 mol of I2 reacts with 2 mol of S2 o3 2-
So 1 mol of IO3- is equivalent to S2 O3 2-
HOW DOES THAT MAKE SENSE?
Your logic is not impeccable.
1 iodate = 3 iodine
and
3 iodine = 2 thiosulfate
Hence
1 iodate = 2 thiosulfate
Original post by APersonYo
2 S2 O3 2- + 3I2 -> 6I- + S4 O6 2-
Whoa Nelly...
2S2O32- -> S4O62- + 2e-
I2 + 2e- -> 2I-
overall:
2S2O32- + I2 -> S4O62- + 2I-
Snot a 3:2 reaction.
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