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Size:  179.6 KB for this question I have a different answer as my integral isn't ln secy . Is this still right though ?Attachment 615170615172
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    (Original post by coconut64)
    Name:  Screenshot_20170129-135115.png
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Size:  179.6 KB for this question I have a different answer as my integral isn't ln secy . Is this still right though ?Attachment 615170615172
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    it looks fine apart from it should say A not 1/A at the end if A = e-c
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    Yeah that's fine. All you've done is said ln(sec) = ln(1/cos) = ln(1) - ln(cos) = -ln(cos)
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