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# Entropy of the system help watch

1. 4Fe+3O2---> 2Fe2O3

Fe=+27.3
FeO=+87.4
O2=+205

(2*87.4)-(4*27.3)+(3*205) =?

I'm not sure if I'm doing the equation right ?
2. (Original post by Hazel99)
4Fe+3O2---> 2Fe2O3

Fe=+27.3
FeO=+87.4
O2=+205

(2*87.4) - (4*27.3)+(3*205) =?

I'm not sure if I'm doing the equation right ?
You lose the entropy of the reactants and gain the entropy of the products.

So you should also subtract the entropy of oxygen.

(2*87.4) - [(4*27.3) + (3*205)] =

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