I thought L cant be 0 cause other PV=nrt doesnt apply because they'd be no volume so I put mine positive constant gradient starting further down the x axis?(Original post by sadasdasdasd)
M proportional to pressure and L is proportional to volume therefore graph is a straight line through the original.

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 15062017 12:59

emmabrindley1
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 15062017 13:01
(Original post by A sad Man)
I thought L cant be 0 cause other PV=nrt doesnt apply because they'd be no volume so I put mine positive constant gradient starting further down the x axis? 
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 15062017 13:43
Anyone get 1.2 for the last question?

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 15062017 13:52
(Original post by emmabrindley1)
what do you reckon the grade boundaries will be ?
I reckon b 3741 4142a, 4647 a* 
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 15062017 13:54
(Original post by Jack077)
Anyone get 1.2 for the last question? 
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 15062017 14:07
(Original post by sadasdasdasd)
dunno exactly what the questions are in order, or the numbers, but can remember the method probably
1) strontium and alpha nucleus
a) velocity of alpha nucleus
energy and mass given therefore 1/2*m*v^2
b) newtons laws to explain motion of strontium
strontium experiences a force as alpha particle experiences a change in momentum?
Repulsion between the two are equal and opposite, also act on each others bodies?
c) calculate v of strontium
M(initial)*v(initial) = M(final)^v(final)
2) ?
3)
4)
5)Thermal physics
a) work out initial n of baloon
use 4/3*pi*r^3 and PV=nRT using initial T, P
b) work out final pressure of baloon before it pops
use 4/3*pi*r^3 for new V and PV=nRT using final T, initial n, final V
c) ratio question
E=3/2KT therefore ratio is T(final)/T(initial)
Help.. pls
2) SHM
 Straight line through the origin suggests SHM
 Why the mass attached to spring went towards the outside when rotated
 State the vertical axis. =v^2 (the graph was in the form v^2=(k/m)R^2. [Derived from F=kR, F=mv2/R.])
 Calculate units for k =kg s^2
 Calculate k/m (i.e. the gradient.) (they gave units of s^2, confirming previous answer.)
 How the mass could be determined (gradient=k/m [k was known], m=(k)/gradient.)
 Experiment for R, F and v using video camera and ruler.
3) Gravity
Mass of Mars is 9.3 times less that of Earth. Mars radius=3400km, Earth radius=6400km
 Calculate g on Mars (I did a lot of working these 2 marks. I certainly over complicated things.)
 Comparison of a probe taking off from the surface of Mars compared to Earth (Resultant force difference due to gravity air resistance.)
 3 Properties for the satellite to remain in the same point above Mars (Equatorial orbit, period = Marian time, same direction as Mars rotation.)
 Calculate the radius of satellite (Using, T^2=(4pi^2/GM)r^3. With the mass of Mars calculated before [6.48x10^23 kg])
 The other satellite had a polar orbit with a particular distance above Mars. Calculate the number of pictures taken per second. (They gave the number of total pictures. [Around 3000.]) (Determine period using T^2 equation [r=radius of Mars+distance above surface] then divide total number by the period.) (answer = 527?).
4) Photon energy, E=mc(theta).
45mA of 130keV electrons for 1.6s.
 Calculate [confirm] the number of electrons [equals 5x10^17]. (=It/e=(45x103)(1.6)/(1.6x1019)=4.5x10^17 electrons)
 Calculate wavelength. (E=130keV=2.08x1014J. E=hc/wavelength>wavelength=9.56x1012 m)
Water cooled thing down by 90%. c=4200, initial temp=17c, final temp=27c, density of the water=1000kgm^3[?]
 Calculate volume of water per second. (Energy cooled by water=(0.9)(number of electrons)(energy of electron)=(0.9)(5x10^17)(2.08x1014)=9360 J. E=mc(theta)>m=E/c(theta)=(9360)/(4200)(2717)=0.22 kg. m per second=(0.22)/(1.6)=0.139 kgs1. volume per second=(0.139)/1000= 1.39x104 m^3 s^1 [Not entirely sure about this one due to forgetting the density.]Last edited by headyb; 15062017 at 14:41. 
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 15062017 14:53
For question one did anyone get like 1.6x10^7 which is approx 2x10^7 cus that seemed a bit off

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 15062017 15:14
(Original post by Super199)
For question one did anyone get like 1.6x10^7 which is approx 2x10^7 cus that seemed a bit off 
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 15062017 15:46
(Original post by adsy9)
I did, thought it was some terrible rounding on their part 
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 15062017 16:27
(Original post by headyb)
I'll see how much I can recall. Unfortunately, I can't quite remember all the numbers, feel free to chime in if anyone else does.
2) SHM
 Straight line through the origin suggests SHM
 Why the mass attached to spring went towards the outside when rotated
 State the vertical axis. =v^2 (the graph was in the form v^2=(k/m)R^2. [Derived from F=kR, F=mv2/R.])
 Calculate units for k =kg s^2
 Calculate k/m (i.e. the gradient.) (they gave units of s^2, confirming previous answer.)
 How the mass could be determined (gradient=k/m [k was known], m=(k)/gradient.)
 Experiment for R, F and v using video camera and ruler.
3) Gravity
Mass of Mars is 9.3 times less that of Earth. Mars radius=3400km, Earth radius=6400km
 Calculate g on Mars (I did a lot of working these 2 marks. I certainly over complicated things.)
 Comparison of a probe taking off from the surface of Mars compared to Earth (Resultant force difference due to gravity air resistance.)
 3 Properties for the satellite to remain in the same point above Mars (Equatorial orbit, period = Marian time, same direction as Mars rotation.)
 Calculate the radius of satellite (Using, T^2=(4pi^2/GM)r^3. With the mass of Mars calculated before [6.48x10^23 kg])
 The other satellite had a polar orbit with a particular distance above Mars. Calculate the number of pictures taken per second. (They gave the number of total pictures. [Around 3000.]) (Determine period using T^2 equation [r=radius of Mars+distance above surface] then divide total number by the period.) (answer = 527?).
4) Photon energy, E=mc(theta).
45mA of 130keV electrons for 1.6s.
 Calculate [confirm] the number of electrons [equals 5x10^17]. (=It/e=(45x103)(1.6)/(1.6x1019)=4.5x10^17 electrons)
 Calculate wavelength. (E=130keV=2.08x1014J. E=hc/wavelength>wavelength=9.56x1012 m)
Water cooled thing down by 90%. c=4200, initial temp=17c, final temp=27c, density of the water=1000kgm^3[?]
 Calculate volume of water per second. (Energy cooled by water=(0.9)(number of electrons)(energy of electron)=(0.9)(5x10^17)(2.08x1014)=9360 J. E=mc(theta)>m=E/c(theta)=(9360)/(4200)(2717)=0.22 kg. m per second=(0.22)/(1.6)=0.139 kgs1. volume per second=(0.139)/1000= 1.39x104 m^3 s^1 [Not entirely sure about this one due to forgetting the density.] 
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 15062017 17:33
(Original post by yelash)
Slightly worried as I don't have any recollection of your Q3! 
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 15062017 17:34
(Original post by Jack077)
Anyone get 1.2 for the last question? 
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 15062017 18:09
(Original post by A sad Man)
Lol I couldn't work out mass of earth because I was in a rush so I just wacked on 6X10^24 because i remembered it from practise questions, So unless they accept that, I've pretty much lost the entire question apart from explanations 
sadasdasdasd
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 15062017 19:58
(Original post by headyb)
I'll see how much I can recall. Unfortunately, I can't quite remember all the numbers, feel free to chime in if anyone else does.
2) SHM
 Straight line through the origin suggests SHM
 Why the mass attached to spring went towards the outside when rotated
 State the vertical axis. =v^2 (the graph was in the form v^2=(k/m)R^2. [Derived from F=kR, F=mv2/R.])
 Calculate units for k =kg s^2
 Calculate k/m (i.e. the gradient.) (they gave units of s^2, confirming previous answer.)
 How the mass could be determined (gradient=k/m [k was known], m=(k)/gradient.)
 Experiment for R, F and v using video camera and ruler.
3) Gravity
Mass of Mars is 9.3 times less that of Earth. Mars radius=3400km, Earth radius=6400km
 Calculate g on Mars (I did a lot of working these 2 marks. I certainly over complicated things.)
 Comparison of a probe taking off from the surface of Mars compared to Earth (Resultant force difference due to gravity air resistance.)
 3 Properties for the satellite to remain in the same point above Mars (Equatorial orbit, period = Marian time, same direction as Mars rotation.)
 Calculate the radius of satellite (Using, T^2=(4pi^2/GM)r^3. With the mass of Mars calculated before [6.48x10^23 kg])
 The other satellite had a polar orbit with a particular distance above Mars. Calculate the number of pictures taken per second. (They gave the number of total pictures. [Around 3000.]) (Determine period using T^2 equation [r=radius of Mars+distance above surface] then divide total number by the period.) (answer = 527?).
4) Photon energy, E=mc(theta).
45mA of 130keV electrons for 1.6s.
 Calculate [confirm] the number of electrons [equals 5x10^17]. (=It/e=(45x103)(1.6)/(1.6x1019)=4.5x10^17 electrons)
 Calculate wavelength. (E=130keV=2.08x1014J. E=hc/wavelength>wavelength=9.56x1012 m)
Water cooled thing down by 90%. c=4200, initial temp=17c, final temp=27c, density of the water=1000kgm^3[?]
 Calculate volume of water per second. (Energy cooled by water=(0.9)(number of electrons)(energy of electron)=(0.9)(5x10^17)(2.08x1014)=9360 J. E=mc(theta)>m=E/c(theta)=(9360)/(4200)(2717)=0.22 kg. m per second=(0.22)/(1.6)=0.139 kgs1. volume per second=(0.139)/1000= 1.39x104 m^3 s^1 [Not entirely sure about this one due to forgetting the density.]
first part of 3) was weird, I just calculated mass of marks first then used that for the next parts
no. of photos for 3) I got 1670 3.s.f.
density for 4) for 1000kgm^3
everything there I got the same pretty muchLast edited by sadasdasdasd; 15062017 at 21:02. Reason: same 
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 15062017 20:35
(Original post by A sad Man)
Lol I couldn't work out mass of earth because I was in a rush so I just wacked on 6X10^24 because i remembered it from practise questions, So unless they accept that, I've pretty much lost the entire question apart from explanations
Oh well hopefully I'm just blocking the pain of rememebring wrong answers from my brainLast edited by yelash; 15062017 at 20:37. 
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 15062017 21:44
(Original post by sadasdasdasd)
for the first part of 2) the direction of the springs acceleration and extension were oppositely directed, this was the first reason for SHM
first part of 3) was weird, I just calculated mass of marks first then used that for the next parts
no. of photos for 3) I got 1670 3.s.f.
density for 4) for 1000kgm^3
everything there I got the same pretty much(Original post by A sad Man)
Lol I couldn't work out mass of earth because I was in a rush so I just wacked on 6X10^24 because i remembered it from practise questions, So unless they accept that, I've pretty much lost the entire question apart from explanations
http://i.imgur.com/J1R0RPB.jpg 
clear_water
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 19062017 11:07
Does anyone have the 2016 papers?

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 19062017 11:32
(Original post by clear_water)
Does anyone have the 2016 papers? 
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 19062017 13:19
Have they increased the time for the G485 paper. Because I did it last year and I'm retaking this year and every paper so far has beem 1h 45mins but the place where I am doing it says 120mins (2h). Is it possible the college just gave extra time?

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 19062017 13:27
(Original post by k_nikolov)
Have they increased the time for the G485 paper. Because I did it last year and I'm retaking this year and every paper so far has beem 1h 45mins but the place where I am doing it says 120mins (2h). Is it possible the college just gave extra time?
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