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differentiating e watch

1. stuck on a question, just need to know:
so if y=e^kx
dy/dx is ke^kx

does that mean if y=ae^kx
then dy/dx= (ak)e^kx?
2. (Original post by Toasticide)
stuck on a question, just need to know:
so if y=e^kx
dy/dx is ke^kx

does that mean if y=ae^kx
then dy/dx= (ak)e^kx?
Yes.
3. Yes, the a is a constant.
4. ah thanks for the quick replies

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Updated: January 31, 2017
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