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C3 function question watch

1. Attachment 616050616056 hi I am a bit stuck on finding the domain for the inverse function of part c. I worked out that the range for fx is fx<1 . So why isn't the domain of the inverse function x<1?

Thanks
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2. (Original post by coconut64)
hi I am a bit stuck on finding the domain for the inverse function of part c. I worked out that the range for fx is fx<1 . So why isn't the domain of the inverse function x<1?

Thanks
Domain of is not as from your sketch... Also yes the range of is less than one but it's not everything below 1. It's not -1 for example.
3. (Original post by RDKGames)
Domain of is not as from your sketch... Also yes the range of is less than one but it's not everything below 1. It's not -1 for example.
Why is that? Because the graph y=1-e^2x does continue all the way down as x is greater than 0. I don't get what you mean.

Thanks
4. (Original post by coconut64)
Why is that? Because the graph y=1-e^2x does continue all the way down as x is greater than 0. I don't get what you mean.

Thanks
In the question the domain of x is given as x is real and x<0. So for x<0, 0<e^2x<1, so what is the range for f? How does this related to the domain for the inverse of f?

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5. (Original post by coconut64)
Why is that? Because the graph y=1-e^2x does continue all the way down as x is greater than 0. (<---- ????) I don't get what you mean.

Thanks
is defined for (read the question for the proper domain... only if this was x>0 would the graph continue all the way down). Take defined for then you have also then and so

That's the range. So that's the domain of the inverse.

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