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    Why is S2O8- first order?
    I did, experiment 1&2 so 0.10/0.05=2 and 35/69 = 0.50 (does this mean 2???)
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    (Original post by Hazel99)
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    Why is S2O8- first order?
    I did, experiment 1&2 so 0.10/0.05=2 and 35/69 = 0.50 (does this mean 2???)
    Because when you halve the concentration of it the time taken doubles.
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    (Original post by SeanFM)
    Because when you halve the concentration of it the time taken doubles.
    So is it directional proportional ?
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    (Original post by Hazel99)
    So is it directional proportional ?
    Yes, I would say so.
 
 
 
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