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Edexcel Mathematics: Core C1 6663 17th May 2017 [Exam Discussion] Watch

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    (6) The functiont(x) at the pointT(3,18)has gradient1.5t(x). Giventhesecondderivateofthefunct iont(x)is2(3x1) sketchthecurveyt(x)clearlysho wingany points of intersection with the coordinate axes.

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    (7) The line l with equation y  ax  b cuts the lines x  2 and x  4 at the pointsAandBwhereyAandyB arepand 2prespectively,p0.

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    The points C and D are the points where the lines x  2 and x  4 cross the coordinate axis. The

    trapeziumABCDhasanareaof24. Findthedistancefromtheorigintoth epointwherelinelcrosses the x axis.

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    Can someone explain why the last line (root)X = -8 does not have a solution. I was thinking you square -8 to get 64 hence X=64
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    (Original post by GenjiPro)
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    Can someone explain why the last line (root)X = -8 does not have a solution. I was thinking you square -8 to get 64 hence X=64
    Because you need two numbers the same that multiply to make -8 (can't be done with real numbers)
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    (Original post by candol)
    Because you need two numbers the same that multiply to make -8 (can't be done with real numbers)
    What do you mean by that? I think the answer is no value for X rooted would give -8. What do you mean by your statement?
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    In sigma questions does anyone know the difference between:

    5(Sigma)1 12=4n^2 =Ar

    Find the value of 1-5 Ar
    and find the value of Un
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    Can someone explain this question to me please
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    (Original post by candol)
    cant login to question
    go onto google and type in C1 mock paper online 2017 and its the second result
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    (Original post by GenjiPro)
    What do you mean by that? I think the answer is no value for X rooted would give -8. What do you mean by your statement?
    I think they mean that you can't have a negative root with real numbers? like type in negative root on your calc, its an error.

    Negative roots are imaginary numbers which you cover in Further maths
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    (Original post by GenjiPro)
    What do you mean by that? I think the answer is no value for X rooted would give -8. What do you mean by your statement?
    Think about it: rootx =-8 is what you got
    root64 does not =-8 so it's not a solution
    Furthermore, no number square rooted can make a negative number
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    (Original post by GenjiPro)
    What do you mean by that? I think the answer is no value for X rooted would give -8. What do you mean by your statement?
    that is exactly what my statement says: (we are in agreement)

    eg sqrt 16 = 4 (or -4) since 4 x 4 = 16

    sqrt -8 is not possible since no two same real numbers multiplied together make -8
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    (Original post by boaconstricta)
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    Can someone explain this question to me please
    anyone able to do this?
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    (Original post by boaconstricta)
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    Can someone explain this question to me please
    Which part are you struggling with? Does it help if I tell you that they've given you the equation for the sum of n values? Look at the "=" sign.
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    (Original post by boaconstricta)
    Can someone explain this question to me please
    (a) Surely it is straight forward??

    (b) a_6=(a_1+a_2+...+a_5+a_6)-(a_1+a_2+...+a_5)
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    when theres 100 on top of the sigma
    am i supposed to look for a pattern

    @RDKGames
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    [QUOTE=RDKGames;71480832](a) Surely it is straight forward??

    I simply don't understand the difference between when it says ar and when it says Un
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    (Original post by boaconstricta)
    For a) does it want me to find the sum of the first 5 terms? Because I don't get the correct answer when I do this.
    Yes.

    It should be [12+4(1)^2]+[12+4(2)^2]+...+[12+4(5)^2]
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    (Original post by RDKGames)
    Yes.

    It should be [12+4(1)^2]+[12+4(2)^2]+...+[12+4(5)^2]
    But the answer in the markscheme is just 12+4x5squared (112) not all of them added together. This is what's confused me.
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    (Original post by wantodothebest)
    Did an online past paper.

    Keeping getting this wrong:

    1. You intergrate an f'(x) to get f(x). They give you a set of coordinates to get C.

    2. They then give you the equation to the normal - i.e 6y + x = 0. Then they tell you to find the coordinate of T.

    I have been trying to do it where I get the gradient of -1/6 of the normal and make it equal to the differentiated formula to try and solve for x. This didnt work.

    I then tried to make the intergrated formula equal y which is -1/6x , rearrange, then differentiate and try to factorise. No luck.

    Do I need to make -1/6 equal 6? Then what??
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    (Original post by RDKGames)
    Yes.

    It should be [12+4(1)^2]+[12+4(2)^2]+...+[12+4(5)^2]
    Actually for part a it's just 12+4(5)^2. All you have to do is substitute the value for n.
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    (Original post by boaconstricta)
    But the answer in the markscheme is just 12+4x5squared (112) not all of them added together. This is what's confused me.
    Oops, misread the question... (the amount of C1 questions I've helped with today must be dragging me down...)

    Anyway, you just sub in the value of 5 for n.
 
 
 
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