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Edexcel Mathematics: Core C1 6663 17th May 2017 [Exam Discussion] Watch

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    (Original post by Maz A)
    anyone????
    find the gradient of the normal using the equation given then use the gradient to get the gradient of the tangent (gradient of normal x gradient of tangent = -1) then equate the gradient of the tangent to dy/dx and find x
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    (Original post by marlodanvers)
    Hey everyone. Good luck for tomorrow.

    Can anyone help with this question of mine really quickly?
    I know it has something to do with completing the square.
    (It's question 2 from the Solomon Paper B)
    (Original post by marlodanvers)
    Hey everyone. Good luck for tomorrow.

    Can anyone help with this question of mine really quickly?
    I know it has something to do with completing the square.
    (It's question 2 from the Solomon Paper B)
    It is
    y = (x + 2)^2 + 5
    = x 2 + 4x + 9,
    a = 4, b = 9
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    (Original post by Maz A)
    anyone????
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    Boom! Hopefully I haven't made any silly mistakes. This is the method you'd be expected to use.
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    (Original post by marlodanvers)
    Hey everyone. Good luck for tomorrow.

    Can anyone help with this question of mine really quickly?
    I know it has something to do with completing the square.
    (It's question 2 from the Solomon Paper B)
    Okay, so.

    if the minimum point is (-2,5)

    And completing the square find the minimum point, it has to look like;

    (x+2)^2 +5

    To get the two in the bracket, think about the original equation, you need to half that a by 2. So times the 2 by 2.

    a=4


    so then you have to think about what you do to get the info out of the bracket. You square the number, minus that from the bracket then add b.

    2^2= 4

    -4+x=5

    5+4=x
    x=9
    b=9

    I hope this is right lol
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    Wish everyone the best of luck, and hope you've all prepared enough to feel comfortable!
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    (Original post by Shadowfire123)
    It is
    y = (x + 2)^2 + 5
    = x 2 + 4x + 9,
    a = 4, b = 9
    (Original post by rhegggg)
    Okay, so.

    if the minimum point is (-2,5)

    And completing the square find the minimum point, it has to look like;

    (x+2)^2 +5

    To get the two in the bracket, think about the original equation, you need to half that a by 2. So times the 2 by 2.

    a=4


    so then you have to think about what you do to get the info out of the bracket. You square the number, minus that from the bracket then add b.

    2^2= 4

    -4+x=5

    5+4=x
    x=9
    b=9

    I hope this is right lol
    yup
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    (Original post by jb10101)
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    Boom! Hopefully I haven't made any silly mistakes. This is the method you'd be expected to use.
    Thank you very much, but the question doesn't state that the there is tangent at the point T on the curve, so wouldn't the gradient of the parallel line (normal gradient) be equal to the gradient of the curve. I.e. dy/dy=-1/4 ?
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    (Original post by rhegggg)
    help

    how do u prove the sum of an arithmetic series
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    (Original post by jb10101)
    Haha that's no problem at all! I've gone through the whole of what coefficients are as I'm not sure how much detail you know already.

    Attachment 647586

    Hopefully this makes more sense!
    Thank You very much. Very much understood now! How did you learn all your mathematics if you don't mind me asking.
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    For inequalities when does the sign change?

    Posted from TSR Mobile
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    (Original post by marlodanvers)
    Hey everyone. Good luck for tomorrow.

    Can anyone help with this question of mine really quickly?
    I know it has something to do with completing the square.
    (It's question 2 from the Solomon Paper B)
    you complete the square, which gives you (x+a/2) inside the brackets. (everything else is irrelevant). The lowest x can ever be is, when the contents of the bracket is equal to 0. Therefore the lowest value of x is when x=-a/2
    You then equate -a/2 to the lowest value of x, which they tell you is -2.
    this gives you the value of a, and i'm sure you can figure out the rest. :-)
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    (Original post by rhegggg)
    help

    how do u prove the sum of an arithmetic series
    I really hope this makes sense!

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    (Original post by LucHawki13)
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    Thank you so much!!
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    (Original post by guy321)
    What paper was that from? I've just attempted the question and I want to check my answers
    (Original post by Rtdsv)
    What paper is that from?

    Posted from TSR Mobile
    www.crashmaths.com/a-level-practice-papers
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    or a slightly more condensed version:

    Sn = a + (a + d) + (a + 2d) + (a + 3d) + ..... (a + (n-2)d) + (a + (n-1)d)
    Reversed Sn = (a + (n-1)d) + (a + (n-2)d) .... (a+ 3d) + (a+2d) + (a + d) + a

    Adding Sn to reversed Sn

    2Sn = 2a + (n - 1)d + 2a + (n-1)d + 2a(n-1)d

    2sn = n[2a + (n-1)d]
    Sn = n/2[2a + (n-1)d]
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    (Original post by jb10101)
    I really hope this makes sense!

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    Oh wow! Thank you so much!!!!!!!
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    (Original post by Maz A)
    Thank you very much, but the question doesn't state that the there is tangent at the point T on the curve, so wouldn't the gradient of the parallel line (normal gradient) be equal to the gradient of the curve. I.e. dy/dy=-1/4 ?
    Hi! There doesn't actually have to be a tangent physically drawn on the curve. No matter where on the curve you are, the (figurative) tangent is equal to the gradient of the curve (dy/dx) and the normal is perpendicular to the tangent. I find it helps to visualise it:

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    As you can see here, the normal is not the gradient of the curve - it's exactly perpendicular to the gradient of the curve.

    This means that the gradient of the tangent, and so dy/dx, must be equal to -1/(gradient of normal).
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    (Original post by rhegggg)
    Thank you so much!!
    No problem, good luck.
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    (Original post by geokid1)
    Thank You very much. Very much understood now! How did you learn all your mathematics if you don't mind me asking.
    Haha don't worry! I've always found that maths comes to me quite easily. It's otherwise a combination of two great maths teachers, and a LOT of practice papers. I've been doing one each of C1, C2 and M1 a week since well before Easter. Though I know it's a little late for that now, I find it helped to familiarise me with the possible types of questions you can get on each paper. You find that there are certain types of question that come up every single year or every couple of years and once you learn how to do them, those marks are in the bag.

    Also, while I was doing my GCSEs I did OCR FSMQ, which is a paper somewhere between IGCSE and AS Level in difficulty. It gave me a huge head start for C1 especially as a lot of the content we learnt for that was exactly the same as C1, and to an extent C2 as well.
 
 
 
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