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Edexcel Mathematics: Core C1 6663 17th May 2017 [Exam Discussion] Watch

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    (Original post by luciferhf)
    In short. Once you've found the co-ordinates of the point C, you'll be able to find the gradient of AD.

    Then you can just setup an equation to figure out

    11 - X = -1
    8 - X = 2
    coordinates of C is 8 and 10
    gradient of AD is 4/3

    what next
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    (Original post by luciferhf)
    P.s. I had my coordinates wrong their.

    K has coordinates (8,10) and the gradient of AD is -1/2

    y2-y1
    ===== --> M
    x2 - x1

    So

    10 - X = -1
    8 - X = 2
    how you got that gradient i think it would be -3/4
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    (Original post by Qer)
    coordinates of C is 8 and 10
    gradient of AD is 4/3

    what next
    Don't mean to be horrible "luciferhf" but your method really over complicates it.

    Qer as long as you know the difference between B and C in terms of X and Y Distances, then you can apply that to (A to D).
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    (Original post by BenSainsbury)
    Don't mean to be horrible "luciferhf" but your method really over complicates it.

    Qer as long as you know the difference between B and C in terms of X and Y Distances, then you can apply that to (A to D).
    thanks
    one more question if you look its part a to find gradient
    AB and BC
    gradient of AB=4/3
    gradient of BC=-3/4


    in mark scheme it shows that it is special case for doing that

    it gives gradient AB=-3/4
    AND BC=4/3

    markschme is also there please look it it if you don't understand what i mean
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    (Original post by Qer)
    thanks
    one more question if you look its part a to find gradient
    AB and BC
    gradient of AB=4/3
    gradient of BC=-3/4


    in mark scheme it shows that it is special case for doing that

    it gives gradient AB=-3/4
    AND BC=4/3

    markschme is also there please look it it if you don't understand what i mean
    That's not something you have to worry about, as long as you know the perpendicular gradient is -1/m then its fine.

    I'm assuming the special case is if someone done 1/m rather than -1/m.
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    (Original post by BenSainsbury)
    That's not something you have to worry about, as long as you know the perpendicular gradient is -1/m then its fine.

    I'm assuming the special case is if someone done 1/m rather than -1/m.
    thanks
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    a) Prove, by completing the square, that the roots of the equation x2 + 2kx + c = 0, where k and c are constants, are −k ± √(k2 − c).

    (4)

    The equation x2 + 2kx ± 81 = 0 has equal roots.

    (b) Find the possible values of k.


    i don't understand how to do part b .
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    (Original post by Qer)
    a) Prove, by completing the square, that the roots of the equation x2 + 2kx + c = 0, where k and c are constants, are −k ± √(k2 − c).

    (4)

    The equation x2 + 2kx ± 81 = 0 has equal roots.

    (b) Find the possible values of k.


    i don't understand how to do part b .
    If there are equal roots then b^2 - 4ac = 0
    So (2k)^2 - 324 = 0
    So k^2 - 81 = 0
    Only solution is when k= +/- 9
    (The -81 in the question has no solutions)
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    the question says y =x^2 -4x +2 not y=x^2 -4x +3 as in your working
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    (Original post by candol)
    the question says y =x^2 -4x +2 not y=x^2 -4x +3 as in your working
    Yes, I realised as soon as I posted.
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    Can someone explain part ii, answer is 2 btw
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    (Original post by GenjiPro)
    Can someone explain part ii, answer is 2 btw
    You could list the terms till you get the first positive answer.
    However a mathematical approach would be to find n when the sequence turns positive and then find the value of that term for that n
    so (note: a= -40 from part i)
    -40 + (n-1)7 >0
    (n-1)7 > 40
    7n -7 > 40
    7n > 47
    n >47/7 so n= 7 (first whole number bigger than 47/7)
    now a + (n-1)d
    so -40 + (7-1)7
    = -40 + 42
    =2
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    As a resit what do you think is the hardest edexcel paper except for June 2016 just gonna do that one to see if I still remember things
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    (Original post by physicsamor)
    As a resit what do you think is the hardest edexcel paper except for June 2016 just gonna do that one to see if I still remember things
    You could try some of the Edexcel Gold papers - they tend to be fairly challenging. Good luck!
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    (Original post by Bubs051213)
    You could try some of the Edexcel Gold papers - they tend to be fairly challenging. Good luck!
    Ah yesI forgot about those ones!thank you
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    (Original post by physicsamor)
    Ah yesI forgot about those ones!thank you
    (Original post by Bubs051213)
    You could try some of the Edexcel Gold papers - they tend to be fairly challenging. Good luck!
    you can try the IAL edexcel which is hardeer and challenging- our coming exam will be something based on the IAL
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    (Original post by physicsamor)
    As a resit what do you think is the hardest edexcel paper except for June 2016 just gonna do that one to see if I still remember things
    Are you resiiting C1?
    have you done the Qs from by past paper questions by topic from June 2005 to June 2014 for each chapter?
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    http://www.physicsandmathstutor.com/...s/c1-by-topic/

    Edexcel - set 2
    it has all the similar qs from each chapter in C1 - all the past paper Qs just for that specifc topic.
    Enjoy!
    I hope you will find it useful.
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    (Original post by hedork)
    any predictions?
    I think it will be harder than the June 2015 but a bit easier than June 2016
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    (Original post by Shadowfire123)
    Are you resiiting C1?
    have you done the Qs from by past paper questions by topic from June 2005 to June 2014 for each chapter?
    Well bear in mind that I'm resitting alongside my a2 subjects lol so I haven't done all the papers at least again (as I did them last year for practise) I have done questions from each topic and like around 4 whole papers but that's all
 
 
 
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