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Isaac Physics: Discharging a Capacitor - What is halving time? Watch

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    I am given that the capacitance is 100μF and the resistance is 200kΩ.
    I have found (using the equation: Time = Resistance x Capacitance) that the time constant is 20s. They are now asking what the halving time is, what is the halving time, how can I find it?
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    (Original post by Aida Karabu)
    I am given that the capacitance is 100μF and the resistance is 200kΩ.
    I have found (using the equation: Time = Resistance x Capacitance) that the time constant is 20s. They are now asking what the halving time is, what is the halving time, how can I find it?
    The halving time is the time taken for the voltage/current/charge of a capacitor to half when discharging the capacitor. To find it, multiply the time constant by ln 2.

    If you equate an exponential decay graph of charge/voltage/current to half its original respective quantity, and rearrange for t, you'll get the half life.
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    (Original post by h3rmit)
    The halving time is the time taken for the voltage/current/charge of a capacitor to half when discharging the capacitor. To find it, multiply the time constant by ln 2.

    If you equate an exponential decay graph of charge/voltage/current to half its original respective quantity, and rearrange for t, you'll get the half life.
    Thanks .
 
 
 
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