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    a. find P(|Z|>0.754)
    b. find P(|Z|<1.78)
    c. f
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    That makes no sense to me.. What are you asking?
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    (Original post by fiyind)
    a. find P(|Z|>0.754)
    b. find P(|Z|<1.78)
    c. f
    firstly, do you understand what the modulus sign (the two vertical lines either side of the Z) means/does?

    The Z lets you know you use the z-tables in the formula book/at the back of the textbook.

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    a) the probability of |Z| being greater than a value n is equal to the probability of Z > n and -Z < -n. On the diagram this is the red lines.

    b) the probability of |Z| being less than a value n is equal to the probability of -n < Z < n. On the diagram this is the white space between -n and n

    c) ?, whatever it asks just draw a diagram and shade the area you require.

    A key point is to notice the symmetry, this will allow you to find the area of regions left of the 0 mark
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    Thank you very much ! very useful
    (Original post by DylanJ42)
    firstly, do you understand what the modulus sign (the two vertical lines either side of the Z) means/does?

    The Z lets you know you use the z-tables in the formula book/at the back of the textbook.

    Name:  s1normal.png
Views: 39
Size:  7.4 KB

    a) the probability of |Z| being greater than a value n is equal to the probability of Z > n and -Z < -n. On the diagram this is the red lines.

    b) the probability of |Z| being less than a value n is equal to the probability of -n < Z < n. On the diagram this is the white space between -n and n

    c) ?, whatever it asks just draw a diagram and shade the area you require.

    A key point is to notice the symmetry, this will allow you to find the area of regions left of the 0 mark
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    TSR Support Team
    Moved to Maths
 
 
 
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