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# Normalised floating point binary watch

1. I'm not quite sure how to convert floating point binary numbers to denary (decimal). These numbers have 5 bits for the exponent and 3 for the mantissa.

01101 010
01000 101

I know hey are both normalised because the first two bits are different.
2. (Original post by Abismuth)
I'm not quite sure how to convert floating point binary numbers to denary (decimal). These numbers have 5 bits for the exponent and 3 for the mantissa.

01101 010
01000 101

I know hey are both normalised because the first two bits are different.
If I remmeber correctly,

First one should be
$\frac{1}{2}X 2^{13}$

Second should be

$(-1 + \frac{1}{4})X2^8$
3. (Original post by Aklaol)
If I remmeber correctly,

First one should be
$\frac{1}{2}X 2^{13}$

$(-1 + \frac{1}{4})X2^8$
I need to convert them to decimal numbers the question says, not sure your answer is the right format. Any idea how to change it to a denary number.
4. (Original post by Abismuth)
I need to convert them to decimal numbers the question says, not sure your answer is the right format. Any idea how to change it to a denary number.
Lol. Put them into a calculator, they're just sums......
That big "X" is a multiplication symbol.
5. (Original post by Aklaol)
Lol. Put them into a calculator, they're just sums......
That big "X" is a multiplication symbol.
Ohhhh, I didn't know it was a multiplication symbol, my bad.

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