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    Does anyone to do this? I've been struggling with it
    Point P is on a bearing of 060' from port O
    Point Q is on a bearing of 130' from port O
    OQ=17 km OP=11km
    Find the distance PQ ( already found, it's 16.8)
    Find the bearing of Q from P
    Please explain step by step, im a bit slow.
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    (Original post by AhmadMJamal)
    Does anyone to do this? I've been struggling with it
    Point P is on a bearing of 060' from port O
    Point Q is on a bearing of 130' from port O
    OQ=17 km OP=11km
    Find the distance PQ ( already found, it's 16.8)
    Find the bearing of Q from P
    Please explain step by step, im a bit slow.


    The first step is to draw a proper diagram. Draw a point O. From O draw a vertical line and call it north. Bearing is the angle the object makes with the north line. Bearing is CLOCKWISE. So draw a straight line inclined at an angle 60 to the north line in the clockwise direction. This is the position of P. Draw another straight line inclined at 130 to the north line. You know OP and OQ. You can get angle POQ which is 70 degrees. Use Cosine rule to find PQ. Draw a new diagram showing OP Oq and PQ and mark in the angle POQ (70). Draw in a north line-this time from P call the top of the line X. Find the angle OQP using sine rule. Draw a second north line from Q Call the top of the line K. This implies that the north line from P and Q are parallel to each other. The sum of angle KQP is 90-angle found by sine rule. Bearing (angle XPQ) is 180-the answer you got right now. Hope this helps!
 
 
 
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