You are Here: Home >< Physics

# Momentum problem watch

1. A) basma has a mass of 59kg and is running at 4m/s, what is her momentum?
B)Basma approaches a road, so she stops quickly. It tAkes her 2.6 seconds to stop. What is the resultant force acting on her?

Part a is 236kg m/s but how do I solve part b? Thanks
2. force=change in momentum / time
3. (Original post by elekro)
force=change in momentum / time
So is it -90.67n
4. (Original post by Joeldan)
So is it -90.67n
why minus?
5. (Original post by elekro)
why minus?
I guess bcoz the change is new momentum (0) - old momentum (236) = -236n/2.6 seconds = -90.76... Is it wrong? If yes please explain thanks

### Related university courses

TSR Support Team

We have a brilliant team of more than 60 Support Team members looking after discussions on The Student Room, helping to make it a fun, safe and useful place to hang out.

This forum is supported by:
Updated: February 4, 2017
Today on TSR

### Exam Jam 2018

Join thousands of students this half term

### Solo - A Star Wars Story

• create my feed
• edit my feed
Poll

The Student Room, Get Revising and Marked by Teachers are trading names of The Student Room Group Ltd.

Register Number: 04666380 (England and Wales), VAT No. 806 8067 22 Registered Office: International House, Queens Road, Brighton, BN1 3XE