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    • Thread Starter

    With respect to the origin...

    The position vectors are:

    L( 4i + 7j + 7k)

    M (i+ 3j+ 2k)

    N(2i + 4j +6k) Find vectors M to L and M to N

    The mark scheme seems to imply that ML is 3i + 4j + 5k

    and MN is (1i+ 1j+ 4k)

    But I'm not sure how you would obtain these answers?
    • Community Assistant

    Community Assistant
    (Original post by APersonYo)
    \vec{AB} = \mathbf{b} - \mathbf{a}

    So direction vector of M to L is the position vector L minus the position vector M.
    • Thread Starter

    (Original post by SherlockHolmes)
    \vec{AB} = \mathbf{b} - \mathbf{a}

    So direction vector of M to L is the position vector L minus the position vector M.
    Thank you
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