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How to work out Mr of molecules with a benzene ring (phenylamine)
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Mina_
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I assumed the benzene ring to be c6h6 and an amine group attached (nh2) therefore mr being 94. But apparently the formula is c6h5h2
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VioletPhillippo
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(Original post by Mina_)
I assumed the benzene ring to be c6h6 and an amine group attached (nh2) therefore mr being 94. But apparently the formula is c6h5h2
I assumed the benzene ring to be c6h6 and an amine group attached (nh2) therefore mr being 94. But apparently the formula is c6h5h2
A benzene ring on its own is C6H6 but as soon as you add a group to the benzene ring (NH2), it is taking a space where one of the hydrogens would have been, so the benzene ring becomes C6H5NH2.
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Mina_
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(Original post by VioletPhillippo)
Hi,
A benzene ring on its own is C6H6 but as soon as you add a group to the benzene ring (NH2), it is taking a space where one of the hydrogens would have been, so the benzene ring becomes C6H5NH2.
Hi,
A benzene ring on its own is C6H6 but as soon as you add a group to the benzene ring (NH2), it is taking a space where one of the hydrogens would have been, so the benzene ring becomes C6H5NH2.
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VioletPhillippo
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(Original post by Mina_)
Ah that explains a lot, thank you!! So attatched to another group, the benzene ring is assumed to be c6h5 ?
Ah that explains a lot, thank you!! So attatched to another group, the benzene ring is assumed to be c6h5 ?
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