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    In a methanol fuel cell, the overall reaction is the combustion of methanol

    The combustion of methanol is

    CH3OH+ 1.5 O2 -> CO2 + 2H2O

    The reaction at the positive electrode i.e. the anode is O2 + 4H+ + 4e- -> 2H2O

    Deduce the half equation for the reaction at the negative electrode in a methanol fuel cell
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    (Original post by APersonYo)
    In a methanol fuel cell, the overall reaction is the combustion of methanol

    The combustion of methanol is

    CH3OH+ 1.5 O2 -> CO2 + 2H2O

    The reaction at the positive electrode i.e. the anode is O2 + 4H+ + 4e- -> 2H2O

    Deduce the half equation for the reaction at the negative electrode in a methanol fuel cell
    That doesn't seem like the right half equation for the positive electrode - at the positive electrode, electrons should be *lost* from anions.
 
 
 
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