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# Maths a level differentiation watch

1. 9) a curve has equation y = x^2 - 3x + 1
a) find the equation of the tangent to the curve at the point where x = 1
b) find the equation of the normal to the curve at the point where x = 3

I got a) as y=-x+2
I got b) as y=-1/6x+3/2
Do people agree?

---Moved to Maths---
2. (Original post by imaan2121)
9) a curve has equation y = x^2 - 3x + 1
a) find the equation of the tangent to the curve at the point where x = 1
b) find the equation of the normal to the curve at the point where x = 3

I got a) as y=-x+2
I got b) as y=-1/6x+3/2
Do people agree?
3. (Original post by imaan2121)
9) a curve has equation y = x^2 - 3x + 1
a) find the equation of the tangent to the curve at the point where x = 1
b) find the equation of the normal to the curve at the point where x = 3

I got a) as y=-x+2
I got b) as y=-1/6x+3/2
Do people agree?
Can you please post future maths subject question in the maths forum please.
5. (Original post by notnek)
I think I did 2(3)-3 = 6 by accident haha, is this working below now right?

for part b)
dy/dx = 2x-3 when x=3 2(3)-3 = 3
therefore the gradient of the normal is -1/3 x
when x=3 y=1
y-1=-1/3 (x-3)
y= -1/3 x +2
6. (Original post by imaan2121)
I think I did 2(3)-3 = 6 by accident haha, is this working below now right?

for part b)
dy/dx = 2x-3 when x=3 2(3)-3 = 3
therefore the gradient of the normal is -1/3 x
when x=3 y=1
y-1=-1/3 (x-3)
y= -1/3 x +2
That's correct now.

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