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    Not too sure what this question is really saying, as if the molecule is tetrahedral then wouldn't both of the above structures be the same? Does it mean that dibromomethane is in fact not tetrahedral then, possibly due to the high electronegativity of bromine? :confused:
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    It is a distorted tetrahedron, but the key is that it shows 3D rotational symmetry.

    There is only one form - worry not.

    Drawn in 2D, there are two forms: the cis and trans forms. You will no doubt get taught about cis-platin in Y13, which in 3D is square planar and therefore has two forms (c.f. this Q).
 
 
 
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