The product of my experiment was phthylylglycyl glycine, this was done by firstly reacting phthylyl glycine with thionyl chloride to produce phthylyl chloride. (then it was recrystallised in petroleum ether)
Then the 'pure' phythyl chloride was dissolved in dry dioxan and then reacted with a suspension of magnesium oxide and glycine &water. This resulting mixture was then acidified by hydrogen chloride.
So my question is what is the role of Dioxan and magnesium oxide? Also, what reagents do i put in the reaction equation for part B of the experiment? Thank you
Dipeptide synthesis experiment Watch
- Thread Starter
- 07-02-2017 20:13
- 07-02-2017 22:32
I'm not familiar with this necessarily, so this is but a suggestion.
The dioxane is just a solvent. I imagine you'd add the phthalylglycyl chloride in dioxane to the glycine and allow the condensation to occur, producing the HCl. The water will react with MgO to form Mg(OH)2, which is basic, and will react with HCl to form MgCl2 and water, perhaps as a means of making the reaction safer to carry out?