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# C3 differentiation watch

1. I've been trying to figure out where I've gone wrong for ages!! Can someone pls help, thank u

---CA Edited post so image was correct way up---
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2. Ugh idk how to rotate it.. I guess this ones better
3. e^2x+2x^2e^2x
e^2x+2x^2e^2x
what about the lne^x^2 that goes at the end!!
5. When you differentiate e^x^2, there's no need to multiply by another x^2.
6. (Original post by pondsteps)

Ugh idk how to rotate it.. I guess this ones better
I did it for you - check your post

I recommend using imgur to upload images then post the link (including the file type e.g. ,jpg) inside [img] tags.
e^2x+2x^2e^2x
crappp i just realised thats one lol thank u
8. (Original post by pondsteps)
what about the lne^x^2 that goes at the end!!
what are you on about LN, there is no need for ln where your intergrating xe^2x
9. (Original post by notnek)
I did it for you - check your post

I recommend using imgur to upload images then post the link (including the file type e.g. ,jpg) inside [img] tags.
okay thank u!
what are you on about LN, there is no need for ln where your intergrating xe^2x
this was dy/dx so not really intergrating ?
11. (Original post by the bear)
this was dy/dx so not really intergrating ?
Sorry Hard, mistakes happen you know? like when hyperthreading my blackjack game, things just tend to fall apart
12. (Original post by pondsteps)
I've been trying to figure out where I've gone wrong for ages!! Can someone pls help, thank u

---CA Edited post so image was correct way up---

Using the product rule y=xe^x2
Let u= x and v= e^x2. Therefore, u'= 1 and v'= 2xe^x2

So using the product rule dy/dx= u.v' + v.u'
This mean dy/dx= (x) . (2xe^x2) + (e^x2) . (1)
This is equal to 2x2e^x2 + e^x2
Factorising this produces e^x2(2x2 + 1), hope this helps simplify it a little.
13. Maz A thanks so much ))
14. (Original post by pondsteps)
Maz A thanks so much ))
Any chance of a rep..? Jks you're very welcome glad it helped .

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