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    solve the question above
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    (Original post by ramshahk)
    solve the question above
    1+cosx= +/-0.5
    cosx= -0.5, -1.5 (-1.5 yields no solutions)
    hence cosx = -0.5

    You can solve the rest- should be quite straightforward from here.
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    (Original post by ramshahk)
    solve the question above
    Sure.

    Can you in return prove that n^m\times n^p = n^{(m+p)} \quad \forall n,p,m \in \mathbb{N} by induction on p? I'm feeling a bit lazy.
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    (Original post by OloMed)
    1+cosx= +/-0.5
    cosx= -0.5, -1.5 (-1.5 yields no solutions)
    hence cosx = -0.5

    You can solve the rest- should be quite straightforward from here.
    its a quarter not half
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    (Original post by RDKGames)
    Sure.

    Can you in return prove that n^m\times n^p = n^{(m+p)} \quad \forall n,p,m \in \mathbb{N} by induction on p? I'm feeling a bit lazy.
    im sorry i havent learnt that yet
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    (Original post by ramshahk)
    its a quarter not half
    ive square rooted both sides of the equation
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    (Original post by ramshahk)
    its a quarter not half
    Protip: learn basic algebra and arithmetic operations before trying to solve trig equations...
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    (Original post by OloMed)
    ive square rooted both sides of the equation
    thaank you
 
 
 

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