Turn on thread page Beta
    • Thread Starter

    Two capacitors of capacitance C1 = 500 nF and C2 = 1.5 μF are connected in series across a cell with emf V = 8V.
    What is the energy stored on C1?

    Any help would be appreciated

    You know that the charge on each capacitor in series is equal. So the total charge is equal to the charge on C_1 and C_2 so Q_T=Q_1=Q_2

    You have your e.m.f (total voltage) and total capacitance (use the equation to work out the total capacitance in series).

    Use Q_T=C_T V_T which will give you your total charge as well as the charge on C_1 (and C_2).

    Use  W = \frac{1}{2} \cdot \frac{Q^2}{C}

    I did not use the two other energy equations because they involve voltage and in series, the voltage across C_1 and C_2 capacitors are different so it would be a longer process.
Favourite type of bread
Help with your A-levels

All the essentials

The adventure begins mug

Student life: what to expect

What it's really like going to uni


Essay expert

Learn to write like a pro with our ultimate essay guide.

Uni match

Uni match

Our tool will help you find the perfect course for you

Study planner

Create a study plan

Get your head around what you need to do and when with the study planner tool.

Study planner

Resources by subject

Everything from mind maps to class notes.

Hands typing

Degrees without fees

Discover more about degree-level apprenticeships.

A student doing homework

Study tips from A* students

Students who got top grades in their A-levels share their secrets

Study help links and info

Can you help? Study help unanswered threadsRules and posting guidelines

Groups associated with this forum:

View associated groups

The Student Room, Get Revising and Marked by Teachers are trading names of The Student Room Group Ltd.

Register Number: 04666380 (England and Wales), VAT No. 806 8067 22 Registered Office: International House, Queens Road, Brighton, BN1 3XE

Write a reply...
Reputation gems: You get these gems as you gain rep from other members for making good contributions and giving helpful advice.