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# Mechanical Maths Pulley Problem watch

1. Attachment 618728Hey! A little stumped on the last part of this question, anyone know how to tackle this?

3. (Original post by Redefine)

Ahh, sorry ;/ (hopefully this works)

4. DIAGRAMS.

Seriously though, draw the whole system out and label the forces you see. You should be able to get simultaneous equations in a and T for the first bit, then the rest is just suvat.
5. (Original post by an_atheist)
DIAGRAMS.

Seriously though, draw the whole system out and label the forces you see. You should be able to get simultaneous equations in a and T for the first bit, then the rest is just suvat.

Hey!

Yes, its actually only the suvat part I'm struggling with
6. (Original post by marinacalder)
Hey!

Yes, its actually only the suvat part I'm struggling with
There are two parts the suvat. The first and last a metres. You can work out the velocity at the end of first a metres and from there how far it travels until it stops
7. (Original post by marinacalder)
Attachment 618728Hey! A little stumped on the last part of this question, anyone know how to tackle this?

As with all mechanics problems, words make no sense!- draw out a neat, labelled diagram, and everything should fall into place.

Show us some working, and I'll be happy to guide you further if you remain stuck.
8. (Original post by OloMed)
As with all mechanics problems, words make no sense!- draw out a neat, labelled diagram, and everything should fall into place.

Show us some working, and I'll be happy to guide you further if you remain stuck.

So sorry to keep bugging you guys
9. (Original post by marinacalder)
Ahh, sorry ;/ (hopefully this works)

5) a) B: 2mg - T = 2ma => T = 2m(g - a)
A: T - 3mg/5 = ma => T = m(3g/5 + a)

So 2(g - a) = 3g/5 + a
=> 2g - 2a = 3g/5 + a
=> 3a = 7g/5
=> a = 7g/15 ms^-2

So T = 2m(8g/15) = 16mg/15 N

b) Modelling A when a > 0: a = 7g/15, s = @, u = 0
So v^2 = u^2 + 2as => v^2 = 2(7g/15)@ = [email protected]/15

Then when a < 0: u^2 = [email protected]/15, a = -3g/5, v = 0
So v^2 = u^2 + 2as => 0 = [email protected]/15 - (6g/5).s
=> (6/5).s = [email protected]/15
=> 3s = [email protected]/3
=> s = [email protected]/9

Dist from edge = [email protected] - @ - [email protected]/9 = [email protected]/9 m

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