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# FP1 watch

1. 2. Use the method of Interval Bisection twice to get approximate solutions to these equations, starting with the given intervals:

a) sin 3x = x2 - 1, -1 < x < 0

2.

a) f(-0.25) = 0.256

....??????
2. f(x) = -x^2 + sin3x + 1
3. (Original post by ckfeister)
f(x) = -x^2 + sin3x + 1

4. (Original post by RDKGames)

How...
5. (Original post by ckfeister)
How...
Plug it into your calculator correctly...
6. (Original post by RDKGames)
Plug it into your calculator correctly...
I got the plus and minus at -x^2 confused, I did -0.5^2 not -(-0.5^2)
7. (Original post by ckfeister)
I got the plus and minus at -x^2 confused, I did -0.5^2 not -(-0.5^2)
Should be , something to look out for more carefully in the future
8. (Original post by ckfeister)
I got the plus and minus at -x^2 confused, I did -0.5^2 not -(-0.5^2)
Are you using degrees or radians? In general you use radians with this sort of question
9. (Original post by alfredholmes)
Are you using degrees or radians? In general you use radians with this sort of question

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