Rearrange it so that you get 12x^-2 then just do what you do… i was just about to say what happens if it's like 12/x with no power but that won't come up at GCSE
Rearrange it so that you get 12x^-2 then just do what you do… i was just about to say what happens if it's like 12/x with no power but that won't come up at GCSE
∫x12dx=12logx+C. That's a good question, it's a shame that not enough students ask themselves it.
Note that x21=x−2 so ∫x212dx=∫12x−2dx and I trust you know how to integrate a power of x?
Hi please can you help me with this question. You had to integrate 1 + 12/x^2 + 48/x^4 + 64/x^6. From this I got -4x^-3 + -48/5x^-5 + -64/7x^-7. You then had to integrate between the values of 2 and 1. It was pretty long so I'm just going to write out my whole working but in the end I got 1531/70. I feel like I've gone wrong somewhere along away possibly in my initial integration or when plugging the values in I don't know please could you help thanks.
Hi please can you help me with this question. You had to integrate 1 + 12/x^2 + 48/x^4 + 64/x^6. From this I got -4x^-3 + -48/5x^-5 + -64/7x^-7. You then had to integrate between the values of 2 and 1. It was pretty long so I'm just going to write out my whole working but in the end I got 1531/70. I feel like I've gone wrong somewhere along away possibly in my initial integration or when plugging the values in I don't know please could you help thanks.
How did you get that? I keep getting 79/70 for the first value and -1277/70 for the second value and so got 1356/70 overall?
Uh, my bad - your integration isn't correct. ∫12x−2=−2+11x−2+1=x−12, same for all your other terms. I think you're getting confused with differentiation.