# What would diagram look like? - mechanics

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#1
Anyone got any tips for this question?
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#2
(Original post by marinacalder)
Anyone got any tips for this question?
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3 years ago
#3
(Original post by marinacalder)
Attached is a diagram showing the forces on the ring and on the 5m particle. You'll need to put in an unknown angle and then resolve vertically and horizontally for the ring and vertically for the particle.
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#4
(Original post by tiny hobbit)
Attached is a diagram showing the forces on the ring and on the 5m particle. You'll need to put in an unknown angle and then resolve vertically and horizontally for the ring and vertically for the particle.
thank you so much for helping me with this! I'm still unsure about how to resolve, and how to find the length of string, and unsure about the force acting to the left of the ring, sorry, I'm teaching myself the advanced higher mechanics course, so key fragments of knowledge might be missing
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3 years ago
#5
The way into this is to consider that the vertical (upwards) component of the string tension acting on the ring must be exactly equal and opposite to the weight of the ring (because its in equilibrium). You don't yet know any of the angles, but let's say the string is inclined upwards at angle theta from the horizontal where it attaches to the ring. You should now be able to express the upwards component of the tension acting on the ring in terms of the tension itself and sine or cosine of theta. But the next thing to note is that you know the tension (in terms of m at least), from the fact that the 5m particle is also in equilibrium. Is that enough pieces of the jigsaw for now? Your immediate target should be theta. Then you can start looking at a right angled triangle of width d and a known angle theta.
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