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FP2 Complex loci help!

The point P represents the complex number z, where
|z+i| = sqrt 2 |z+i/2| .
Show that the locus of P can be expressed as |z| = 1/sqrt2
Now I've done this by turning z into Cartesian and simplifying but I was wondering why I can't divide both sides by |z+i/2| and take the reciprocal of both sides to get
|z+i/2|/|z+i| = 1/sqrt2
Since everything else in the equation is the same, I expected |z+i|/|z+i/2| to simplify into
|z|
but it didn't and I was wondering why not. Any help would be much appreciated. Thanks
(edited 7 years ago)
Original post by astudent...
The point P represents the complex number z, where
|z+i| = sqrt 2 |z+i/2| .
Show that the locus of P can be expressed as |z| = 1/sqrt2
Now I've done this by turning z into Cartesian and simplifying but I was wondering why I can't divide both sides by |z+i/2| and take the reciprocal of both sides to get
|z+i|/|z+i/2| = 1/sqrt2
Since everything else in the equation is the same, I expected |z+i|/|z+i/2| to simplify into
|z|
but it didn't and I was wondering why not. Any help would be much appreciated. Thanks


z+i2z+i=z    z=12 \displaystyle \frac{|z+\frac{i}{2}|}{|z+i|} = |z| \iff |z| = \frac{1}{\sqrt{2}}

if z+i2z+i \displaystyle \frac{|z+\frac{i}{2}|}{|z+i|} simplified to give z \displaystyle |z| you would be saying that no matter what z+i2z+i \displaystyle \frac{|z+\frac{i}{2}|}{|z+i|} is equal to, z \displaystyle |z| will always equal that value which you can see clearly isnt true for z=0 ie z+i2z+i0 \displaystyle \frac{|z+\frac{i}{2}|}{|z+i|} \neq 0 for z=0 \displaystyle z=0

this is a kind of special case where the solution for z when z+i2z+i=12 \displaystyle \frac{|z+\frac{i}{2}|}{|z+i|} = \frac{1}{\sqrt{2}} is z=12 \displaystyle |z| = \frac{1}{\sqrt{2}} itself


if thats hard to wrap your head around think about this instead, as its effectively the same thing;

x2+2x=1    x=1 \displaystyle x^2 + 2x = -1 \iff x = -1

however that does not mean that x2+2x=x \displaystyle x^2 + 2x = x for every value of x, it just so happens that x2+2x=1 \displaystyle x^2 + 2x = -1 gives x=1 \displaystyle x=-1 as a solution.

x2+2x=3 \displaystyle x^2 + 2x = 3 doesnt mean x=3 \displaystyle x = 3 just because it worked for -1

does that make sense?
Original post by DylanJ42
z+i2z+i=z    z=12 \displaystyle \frac{|z+\frac{i}{2}|}{|z+i|} = |z| \iff |z| = \frac{1}{\sqrt{2}}

if z+i2z+i \displaystyle \frac{|z+\frac{i}{2}|}{|z+i|} simplified to give z \displaystyle |z| you would be saying that no matter what z+i2z+i \displaystyle \frac{|z+\frac{i}{2}|}{|z+i|} is equal to, z \displaystyle |z| will always equal that value which you can see clearly isnt true for z=0 ie z+i2z+i0 \displaystyle \frac{|z+\frac{i}{2}|}{|z+i|} \neq 0 for z=0 \displaystyle z=0

this is a kind of special case where the solution for z when z+i2z+i=12 \displaystyle \frac{|z+\frac{i}{2}|}{|z+i|} = \frac{1}{\sqrt{2}} is z=12 \displaystyle |z| = \frac{1}{\sqrt{2}} itself


if thats hard to wrap your head around think about this instead, as its effectively the same thing;

x2+2x=1    x=1 \displaystyle x^2 + 2x = -1 \iff x = -1

however that does not mean that x2+2x=x \displaystyle x^2 + 2x = x for every value of x, it just so happens that x2+2x=1 \displaystyle x^2 + 2x = -1 gives x=1 \displaystyle x=-1 as a solution.

x2+2x=3 \displaystyle x^2 + 2x = 3 doesnt mean x=3 \displaystyle x = 3 just because it worked for -1

does that make sense?


Thanks so much, yes that makes a lot of sense. So it's really just like finding the intercept of a graph but with z. and instead of an intercept. all the points on the circle with centre origin and radius 1/sqrt2 will be a solution? Thanks a bunch for the help!!
Original post by astudent...
The point P represents the complex number z, where
|z+i| = sqrt 2 |z+i/2| .
Show that the locus of P can be expressed as |z| = 1/sqrt2
Now I've done this by turning z into Cartesian and simplifying but I was wondering why I can't divide both sides by |z+i/2| and take the reciprocal of both sides to get
|z+i|/|z+i/2| = 1/sqrt2
Since everything else in the equation is the same, I expected |z+i|/|z+i/2| to simplify into
|z|
but it didn't and I was wondering why not. Any help would be much appreciated. Thanks


the red part is the wrong way up.
Original post by the bear
the red part is the wrong way up.


whoops, thanks, I've edited it now.

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