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Mechanics Differential Equations homework

My homework question is:
A particle of mass m is moving along a straight horizontal line. At time t the particular has speed v. Initially the particle is at the origin and has speed u. As it moves, the particle is subject to resistance force of magnitude mkv^2
Show that v=u/(1+ukt)

Any help atall would be great i keep ending up with different answers every time I try it
Original post by AbbyFrancome
My homework question is:
A particle of mass m is moving along a straight horizontal line. At time t the particular has speed v. Initially the particle is at the origin and has speed u. As it moves, the particle is subject to resistance force of magnitude mkv^2
Show that v=u/(1+ukt)

Any help atall would be great i keep ending up with different answers every time I try it


F=ma=mkv2dvdt=kv2,v(0)=uF=ma=-mkv^2 \Rightarrow \frac{dv}{dt}=-kv^2, \quad v(0)=u

Why are you getting different answers?

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