JoyBrowne
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HELLO, PLEASE HOW DO I SOLVE THIS QUESTION AND WHAT FORMULA SHOULD I USE IN SOLVING THIS QUESTION BELOW:
* A PIECE OF COPPER BALL OF MASS 20g AT 200 DEGREE CELSIUS IS PLACED INA COPPER CALORIMETER OF MASS 60g CONTAINING 50g OF WATER AT 30 DEGREES CELSIUS,IGNORING HEAT LOSSES,CALCULATE THE FINAL STEADY TEMPERATURE OF THE MIXTURE. (SPECIFIC HEAT CAPACITY OF WATER=4.2Jg/k)
I NEED URGENT HELP. THANKS
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cakeboi
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(Original post by JoyBrowne)
HELLO, PLEASE HOW DO I SOLVE THIS QUESTION AND WHAT FORMULA SHOULD I USE IN SOLVING THIS QUESTION BELOW:
* A PIECE OF COPPER BALL OF MASS 20g AT 200 DEGREE CELSIUS IS PLACED INA COPPER CALORIMETER OF MASS 60g CONTAINING 50g OF WATER AT 30 DEGREES CELSIUS,IGNORING HEAT LOSSES,CALCULATE THE FINAL STEADY TEMPERATURE OF THE MIXTURE. (SPECIFIC HEAT CAPACITY OF WATER=4.2Jg/k)
I NEED URGENT HELP. THANKS
Hi,

The specific heat capacity of something is simply the amount of heat energy required to raise 1g of that substance or object by 1°C.
It is given by the formula Q = mcΔT, where Q is the energy transferred (J), m is the mass of the substance (kg), c is the specific heat capacity, and ΔT is the temperature change (°C).

Hope this helps!
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Johnzando
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Given that the S. H. C of water is 4.2J per g per k and S. H. C of copper is 0.4J per g per k. Heat lost by copper=Heat gained by copper calorimeter heat gained by water.Mc(200-final temp) =Mc(ff-fw) Mwcw(ff-fw)20*0.4(200-ff)=60*0.4(ff-30) 50*0.4(ff-30)8(200-ff)=24(ff-30) 210(ff-30)1600-8ff=24ff-720 210ff-6300Collect like term together, we have1600 720 6300=ff(210 24 8)8620=242ffDivide both side by 2428620/242=242/242ff=35.6k since S. H. C is in J per gramme per kelvin
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Eimmanuel
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(Original post by Johnzando)
Given that the S. H. C of water is 4.2J per g per k and S. H. C of copper is 0.4J per g per k. Heat lost by copper=Heat gained by copper calorimeter heat gained by water.Mc(200-final temp) =Mc(ff-fw) Mwcw(ff-fw)20*0.4(200-ff)=60*0.4(ff-30) 50*0.4(ff-30)8(200-ff)=24(ff-30) 210(ff-30)1600-8ff=24ff-720 210ff-6300Collect like term together, we have1600 720 6300=ff(210 24 8)8620=242ffDivide both side by 2428620/242=242/242ff=35.6k since S. H. C is in J per gramme per kelvin
Welcome to TSR.

I understand that you want to help. It would be better that you help on the more recent threads dated this year 2019.

It would also be better that you write in point forms especially when you are showing calculation.
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