Fibre optics problem
The second attachment won't work but the question is "For a fibre optic cable, show that the time difference between a signal taking path A and a signal taking path B (on the diagram) is approximately 0.4 nanoseconds." Core diameter = 0.6mm.
I have absolutely no clue how to do that. Could someone point me in the right direction?
Speed = distance/time
Speed = speed of light
Posted from TSR Mobile
Speed = speed of light
Posted from TSR Mobile
Original post by Kyx
It wants a diagram though (so presumably I need some kind of geometry).
Original post by Sonechka
It wants a diagram though (so presumably I need some kind of geometry).
internal reflection obeys the same rules as any other reflection... angle of incidence = angle of reflection... so the ray will always be travelling at either +30°
to the side of the fibre or at -30° to the side of the fibre.
so path B is the hypotenuse of a triangle with adjacent length 1km
note also that cos (+θ) = cos (-θ)
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