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C3 trig proof help

(tanx+cotx)(sinx+cosx)=secx+cosecx

For this proof, I know one way you can solve it is do solve the first bracket first but changing into a single fraction. But I have expanded everything out, where can I go from there? Thanks14883083082722093932620.jpg
(edited 7 years ago)
Original post by coconut64
(tanx+cotx)(sinx+cosx)=secx+cosecx

For this proof, I know one way you can solve it is do solve the first bracket first but changing into a single fraction. But I have expanded everything out, where can I go from there? Thanks14883083082722093932620.jpg


group terms and put them over a common denominator (sin2θcosθ+cosθ)+(cos2θsinθ+sinθ)\displaystyle (\frac{sin^2\theta}{cos\theta} + cos\theta) + (\frac{cos^2\theta}{sin\theta} + sin\theta)

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