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username2821194
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#1
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#1
Why is it that when you solve Solve t=2π√l/g you square both sides so the 2π to make tsqrd=4πsqrd ,but when it comes to getting rid of the fraction I thought its the same princicple so you do the same thing to both sides so multiply by G because you do the same to top and bottom but apparetly you just multiply the g by the t to give gt sqred=4 πsqred l? Why is this?
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Notnek
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(Original post by wfisom)
Why is it that when you solve Solve t=2π√l/g you square both sides so the 2π to make tsqrd=4πsqrd ,but when it comes to getting rid of the fraction I thought its the same princicple so you do the same thing to both sides so multiply by G because you do the same to top and bottom but apparetly you just multiply the g by the t to give gt sqred=4 πsqred l? Why is this?
Thanks
Your question is unclear.

If you square both sides you get \displaystyle t^2 = 4\pi^2 \frac{l}{g^2}

Are you happy with this part? It may be easier for us if you show all the working but make it clear which part you're unsure about.
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RDKGames
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#3
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(Original post by notnek)
If you square both sides you get \displaystyle t^2 = 4\pi^2 \frac{l}{g^2}
Typo \mapsto t^2 = 4\pi^2 \frac{l}{g}

EDIT: Never mind, I just assumed that he meant the pendulum time period equation, could be just \sqrt{l}. Looks too ambiguous

(Original post by wfisom)
Why is it that when you solve Solve t=2π√l/g you square both sides so the 2π to make tsqrd=4πsqrd ,but when it comes to getting rid of the fraction I thought its the same princicple so you do the same thing to both sides so multiply by G because you do the same to top and bottom but apparetly you just multiply the g by the t to give gt sqred=4 πsqred l? Why is this?
Thanks
Assume you meant t=2\pi \sqrt{\frac{g}{l}}

You have t=2 \pi \sqrt{\frac{g}{l}} and if you square both sides you get  t^2=(2 \pi \sqrt{\frac{l}{g}} )^2=(2\pi)^2( \sqrt{\frac{l}{g}} )^2=4\pi\cdot \frac{l}{g}


Then continue to solve for whatever you need to.
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Notnek
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#4
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(Original post by RDKGames)
Typo \mapsto t^2 = 4\pi^2 \frac{l}{g}
Wasn't a typo, it looked like the OP only had a square root on the numerator.

But you're right - I should have assumed it was the pendulum formula.
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Plücker
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#5
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(Original post by Morgan Kurt)
Make x the subject T=2π√x/g
You have arrived just in time to save us all from confusion.
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Notnek
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#6
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(Original post by Plücker)
You have arrived just in time to save us all from confusion.
I've been waiting 4 years and now I can finally rest.
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