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Maths Homework: Simultaneous & Equation of a Circle? Watch
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Help me please!
"Using the grid below (an -8x8 graph), design a simultaneous equations solution with one circle and one straight line that have no solutions.
Show that this is true graphically and using an algebraic method."
Any help would be appreciated as I have no idea.
"Using the grid below (an -8x8 graph), design a simultaneous equations solution with one circle and one straight line that have no solutions.
Show that this is true graphically and using an algebraic method."
Any help would be appreciated as I have no idea.
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#2
(Original post by poppydoodle)
Help me please!
"Using the grid below (an -8x8 graph), design a simultaneous equations solution with one circle and one straight line that have no solutions.
Show that this is true graphically and using an algebraic method."
Any help would be appreciated as I have no idea.
Help me please!
"Using the grid below (an -8x8 graph), design a simultaneous equations solution with one circle and one straight line that have no solutions.
Show that this is true graphically and using an algebraic method."
Any help would be appreciated as I have no idea.
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(Original post by RDKGames)
Firstly, when you are solving two equations simultaneously, what do the pairs of solutions that you find actually represent graphically?
Firstly, when you are solving two equations simultaneously, what do the pairs of solutions that you find actually represent graphically?
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#4
(Original post by poppydoodle)
They cross?
They cross?
So when it comes to your question, what would it mean graphically if the line and the circle would have no solutions when you're solving them simultaneously?
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#5
no solution = no intersection
equation of a circle = (x-h)^2 + (x-k)^2 = r^2 where the centre is (h,k), r = radius
equation of straight line = y = mx+c
equation of a circle = (x-h)^2 + (x-k)^2 = r^2 where the centre is (h,k), r = radius
equation of straight line = y = mx+c
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