# Maths Help

#1
Okay so I thought this question would be easy but it had 3 sets of numbers for an inverse proportion...

question:

y is inversely proportional to square root of x.

x = 9 , y = c (also a constant)
x = 25 , y = c - 16

show that when x = 36, y = 20

I don't get how to get rid of c...

???????
0
5 years ago
#2
y is inversely proportional to x^-0.5, so y=k(an arbitrary constant) times x^-0.5
If you substitute your known values of x into the equation, you can find k, and then you just sub in x=36.
0
5 years ago
#3
(Original post by Alicezworld)
Okay so I thought this question would be easy but it had 3 sets of numbers for an inverse proportion...

question:

y is inversely proportional to square root of x.

x = 9 , y = c (also a constant)
x = 25 , y = c - 16

show that when x = 36, y = 20

I don't get how to get rid of c...

???????
How did you try getting rid of c?
0
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