Original post by Mina_
An excess of methanol was mixed with 12 g of ethanoic acid and an acid catalyst. At equilibrium the mixture contained 8 g of methyl ethanoate. The percentage yield of ester present was..?
I got 8/12 x 100 which gave me 66.6 but this was incorrect
I got 8/12 x 100 which gave me 66.6 but this was incorrect
Percentage yield = (actual moles in process) / (predicted moles)
I assume the predicted is if all 12g react.
Try working out the yield in terms of moles.
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