# Kc question

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#1
Question : http://www.ocr.org.uk/Images/319513-...d-elements.pdf

For question 3 iv) the question states that only 1 mole of so2 is now used and there is an excess amount of O2. Surely the new equation will be this
SO2+0.5O2-> SO3 I don't quite get why they still relate to the previous part of the question which shows that there are two moles of SO2.

Thanks
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3 years ago
#2
(Original post by coconut64)
Question : http://www.ocr.org.uk/Images/319513-...d-elements.pdf

For question 3 iv) the question states that only 1 mole of so2 is now used and there is an excess amount of O2. Surely the new equation will be this
SO2+0.5O2-> SO3 I don't quite get why they still relate to the previous part of the question which shows that there are two moles of SO2.

Thanks
It's the molar ratios that matter, and they're constant no matter how you change the amount of SO2
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#3
(Original post by h3rmit)
It's the molar ratios that matter, and they're constant no matter how you change the amount of SO2
but the molar ratio is the number of moles though. What do you mean by that? thanks
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3 years ago
#4
(Original post by coconut64)
but the molar ratio is the number of moles though. What do you mean by that? thanks
As in the molar ratios of the chemical equation.
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#5
(Original post by h3rmit)
As in the molar ratios of the chemical equation.
But the question states that the mole ratio of so2 has been changed to 1 though
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3 years ago
#6
(Original post by coconut64)
But the question states that the mole ratio of so2 has been changed to 1 though
The amount of SO2 has been changed to 1, but the molar ratio of the equation is still constant, since you're doing the same reaction -however much oxygen you have, you still need double the amount of sulphur dioxide to make your products.
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