username2315623
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#1
Report Thread starter 5 years ago
#1
Could someone explain to me how:

6 divided by root2 is 3root2
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Verish
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#2
Report 5 years ago
#2
You rationalise the denominator by multiplying both top and bottom by root2. That gives you 2 on the bottom and 6root2 on the top which simplifies to the answer
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anon19283746
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#3
Report 5 years ago
#3
first way. 6 = root36, root 36 divided by root 2 = root18, root 18 = root9 times root 2, root 9 = 3, 3 times root 2 = 3root2
second way. rationalise denominator. making it 6root 2 divided by 2= 3root2
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Rexar
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#4
Report 5 years ago
#4
If you take 6/root2 and times both sides by root2 you get (6*root2)/(root2*root2). Root2*roots 2 is just 2 so this gives (6root2)/2 And since 6/2 is 3 this gives 3root2. If your conused look into rationalising the denominator
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username2512877
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#5
Report 5 years ago
#5
6/sqrt(2) = 6/sqrt(2) * sqrt(2)/sqrt(2)

(6*sqrt(2))/sqrt(2)^2 = 6*sqrt(2)/2 = 3*sqrt(2)
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Philip-flop
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#6
Report 5 years ago
#6
You have to rationalise the denominator by...

 \frac{6}{\sqrt{2}} \times \frac{\sqrt{2}}{\sqrt{2}}

Since dividing a number by itself gives 1 it'll have no numeric effect on the equation, it merely just changes the look of it
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