# A-level Physics Help Needed!!!

Watch
Announcements
#1

here is the url http://filestore.aqa.org.uk/resource...74083A-SQP.PDF

0
3 years ago
#2
Assume we start from the beginning where pd is 0 this means in one second the pd is now 98mv and the 65uA of charge is stored by capacitor thus we can use the equation c=qv to find capacitance. This value is something like 655uF I think off the top of my head, Given they say there is a -+5 tolerance on the nominal capacitance of 680uF so capacitance varies around 644 to 700uF so this value is within the tolerance.
1
X

new posts
Back
to top
Latest
My Feed

### Oops, nobody has postedin the last few hours.

Why not re-start the conversation?

see more

### See more of what you like onThe Student Room

You can personalise what you see on TSR. Tell us a little about yourself to get started.

### Poll

Join the discussion

#### Current uni students - are you thinking of dropping out of university?

Yes, I'm seriously considering dropping out (86)
13.96%
I'm not sure (29)
4.71%
No, I'm going to stick it out for now (195)
31.66%
I have already dropped out (13)
2.11%
I'm not a current university student (293)
47.56%