ace-master
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i dont understand 02.6 and 02.7 could someone please help me?

here is the url http://filestore.aqa.org.uk/resource...74083A-SQP.PDF

thanks in advance
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Mahamed17
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Assume we start from the beginning where pd is 0 this means in one second the pd is now 98mv and the 65uA of charge is stored by capacitor thus we can use the equation c=qv to find capacitance. This value is something like 655uF I think off the top of my head, Given they say there is a -+5 tolerance on the nominal capacitance of 680uF so capacitance varies around 644 to 700uF so this value is within the tolerance.
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